Class Note
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Circuit build
Pre-Lab
This lab today is to aply different signals with multiple frequency components. The circuit consisted of 1kohm and series with and capacitor and also parallel to another 1kohm resistors
In the prelab we calculate the magnitude that response to the circuit. we know the s = jw and we simply it to get 1 / (RCS +2)
We first created a custom waveform 20(sin(1000πt)+sin(2000πt)+sin(20,000πt)) and sinusoidal sweep function.
20(sin(1000πt)+sin(2000πt)+sin(20,000πt)) function
At this graph we can see the high frequency part is more suppressed than the low frequency part.
500 Hz
1000 Hz
10,000 Hz
sinusoidal sweep
This one we see that frequency is being suppressed more .
Also being suppressed a lot here
As what we know from handout when the lower frequencies, the capacitor has infinite impedance, the circuit becomes a simple voltage divider which will simply divide income voltage half.
w = 0 => Vout/ vin = 1/2
However right now we were playing a high frequencies, but we didn't get our Independence to zero . our capacitor didn't act like short circuit.
w = infinite => Vout/Vin =0
Summary: what I learned today is how frequency response. The frequency response the circuit is determined by the depend on the transfer function H(w) . The frequency dependent ratio of a phasor output to phasor input .
Important function:
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